The height $h$ of an arrow in feet is modeled by $h(t) = -16t^2 + 63t + 4$, where $t$ is the time in seconds since the arrow was shot. How long is the arrow in the air?
Could someone explain where to start? I am stumped on this question.
2026-04-09 13:22:52.1775740972
How long is an arrow in the air?
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HINT: Solve to find the time $t$ at which $h(t)$, the height of the arrow above the ground, is $0$. This is just a matter of solving a quadratic equation.