Yesterday I posted this question. The Task was:
Show that there is a greatest number $m$ for which the following statement is true! There is a convex polygon, under whose inner angles exactly $m$ are acute
The solution was, that there is a maximum of $3$.
Now I have asked myself how many acute angles ($m < 90°$) can have a polygon if it is not convex and overlap-free.
Note:
look here, there can be more then $\frac {n}{2}$ such angles, but I don't see an reason why there's a maximum amount of acute interior angles (and there is one)!
Does anyone have an idea?
