How many digits are there in the product of $(3698765432123456789)$ and $(345678909876543)$?

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How many digits are there in the product of $(3698765432123456789)$ and $(345678909876543)$? I could not find any formula to solve it and I stuck in it. Can you suggest any formula or way for it?

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The first number has $19$ digits, and the second has $15$. If you write them in scientific notation as $a\times 10^{18}$ and $b\times 10^{14}$, the product is $ab\times 10^{32}$. It’s clear that $10<ab<100$, so $ab\times 10^{32}$ has $2+32=34$ digits.