How many endomorphisms $(\mathbb{N},\times)$ has? Like object in Mon category

92 Views Asked by At

I was told that there is only one morphism in $Mon$ category for this object $(\mathbb{N},\times)$. But why?

I think that we can write every natural number as the product of a certain set of prime numbers. So we can say that the set of primes forms the basis of this monoid $(\mathbb{N},\times)$, that is, linear combinations with positive integer coefficients (powers) make up the entire set of supports for the structure of this monoid: for any $n\in\mathbb{N}$, $n = p_1^{g_1}\times\cdots\times p_i^{g_i}$, where $\forall p_j \in \{p_1,p_2,\cdots\}$ -- basis, and $\forall g_j\in \mathbb{Z_{>0}}$. And we can make some transpositions on the elements of the basis $\{p_1,p_2,\cdots\}$ thereby defining the morphism (where always $1$ going to $1$ by this morphism). So we have infinite number of morphisms, I am right?