Nina cooked 121 hotdogs for the Christmas party. There were 16 male and 18 female guests. Each male guest ate 1 more hotdog than each female guest. Each of the female guests, including Nina, ate equal number of hotdogs. How many hotdogs did each male guest eat?
2026-03-28 08:09:25.1774685365
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How many hotdogs did each male guest eat?
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Let each female eat x hotdogs.
We have 19 females including Nina.
So hotdogs eaten by females = 19x
Each male eat 1 more hotdog than by female. So hotdog eaten by each male = (x + 1)
And we have 16 male so total hotdogs eaten by them = 16(x + 1)
Total hotdogs eaten by male and female = 121
19x + 16(x + 1) = 121
19x + 16x + 16 = 121
35x = 121 - 16
35x = 105
x = 3
So each female eat 3 hotdogs.
And each male eat 4 hotdogs.
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Assume all hotdogs are eaten, i.e. number of hotdogs eaten is $121$.
If each of $16$ male guests did not eat the $1$ hotdog more than each of the female guests,
- the total number of hotdogs eaten would have been $121-16=105$
- all guests (including Nina) would have eaten the same number of hotdogs each which is $105\div 35=3$
However, since each male guest ate $1$ more, the number of hotdogs eaten by each male guest is $\color{red}4$.
Let $x$ be the number of hotdogs that one female guest ate . Then we have :
$$16(x+1)+18x+x=121$$ $$16x +16+19x=121$$ $$35x=121-16$$ $$35x=105$$ $$x=3$$
So number of hotdogs that each male guest ate is $4$ .