(a, b have to be integers)
Assuming a,b both positive, we get $ab<b^{2}$
Therefore, $b> \sqrt{20!}$
Similarly, $a < \sqrt{20!}$
I am stuck after this. Help?
2026-03-25 18:56:25.1774464985
How many reduced fractions a/b such that ab=20! and 0 < a/b < 1?
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Hint: $a<b$ and they have no common prime factors. Now make a list of all the prime factors of $20!$....