How would I add the displacement using the Component method. So I am Given the Following:
d = 20cm [N] d2 =50cm [S 35 E] d3 =100cm [ W 15 S]
what I did was I first drew them and after that I added all the x components and the y components.
After that I found the square root of that and then i found the angle but when i did all of that i got the final answer of 117 [ S 1 E ] which is wrong. The real answer should be 83cm [S 49 W].
I didn't get how they got it so that's why i am asking you so I know how to do it.
it would be good if you can show me step by step.
You describe what you did but do not say specifically how you did it or what partial results you got. In terms of components, the three vectors are (20, 0), (-50 cos(35), 50sin(35)), (-100 sin(15), -100 cos(15)). Are those what you got? Doing the trig functions, those are (20, 0), (-41, 28.6), and (-25.9, -96). Adding those, (-46.9, -67.4). That has length 82.1 (probably "round off error" from your "83". The angle is given by the arctan(67.4/46.9)= arctan(1.437)= 55.1 "S of W". (A ways off your "49" degrees)