How to arrive to this formula $A=\sqrt{s(s-a)(s-b)(s-c)}?$

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Heron's formula for area of any tinangles $$A=\sqrt{s(s-a)(s-b)(s-c)}\tag1$$

Where $a,b$ and $c$ are the sides of the triangle. $s$ is the semi-perimeter of the triangle.

$$s={a+b+c\over 2}$$

How did they derive this formula $(1)$?