A simple random sample of size 10 from $N(\mu,\sigma^2)$ gives $98$% confidence interval$(20.49,23.51)$. The null hypothesis is $H_0: \mu=20.5$ against $H_1: \mu \ne20.5$.
What will be the confidence level for accepting this hypothesis?
I am trying to solve this problem but unable to understand how to extract confidence level from the interval,Can anyone help please?
2026-03-30 12:04:13.1774872253
How to calculate confidence level from confidence interval?
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It says that it is a $98\%$ confidence interval, so the confidence is $98\%$. If you mean
Then this is a $98\%$ CI $\iff$$(1-\alpha)\%$ CI. This implies that the significance level is $\alpha = 1-.98 = .02$.