$C : x^{2/3} + y^{2/3} = 1$
I'm stuck, so any tip will be helpful
Thanks in advance!
The solution for $y$ is $$y(x) = (1 - x^{2/3})^{3/2}$$
The area $A$ is given by
$$A=4\int_0^1 y(x) dx=\frac{3\pi}{8}$$
The length $L$ of the curve is given by:
$$ L=4\int_0^1dx\sqrt{(y'(x))^2+1}=6$$
Copyright © 2021 JogjaFile Inc.
The solution for $y$ is $$y(x) = (1 - x^{2/3})^{3/2}$$
The area $A$ is given by
$$A=4\int_0^1 y(x) dx=\frac{3\pi}{8}$$
The length $L$ of the curve is given by:
$$ L=4\int_0^1dx\sqrt{(y'(x))^2+1}=6$$