Let $l$ be the length of the portion of the curve $x=x(y)$ between the lines $y=1$ and $y=2$ where $x(y)$ staisfy $\sqrt \frac {1+y^2+y^4}{y} \ , x(1)=0$. Then find $l$ .
The main thing I didn't get in this question is $x(y)$ satisfy $\sqrt \frac {1+y^2+y^4}{y}$ what does it imply?
According to me the function will be of this type $$x(y)=(y-1)f(y)$$ Where $f(y)$ is a function which have to find it to evaluate the arc length. $$l=\int_{1}^{2} \sqrt { ( \frac {dx}{dy})^2 +1} \ \ dy$$
See here Exact image of question.
The correct answer is 2.195