I do not reach the correct proportions.
Having no sides with numbers or letters I get many relationships, because I put letters to everything not known.
Obviously,$\triangle EFC$ and $\triangle AFD$ similar triangles so $$\frac { A\left( \overset { \triangle }{ EFC } \right) }{ A\left( \overset { \triangle }{ AFD } \right) } =\frac { { \left( 2m \right) }^{ 2 } }{ { \left( 3m \right) }^{ 2 } } =\frac { 4 }{ 9 } $$ anf we get that $$A\left( \overset { \triangle }{ AFD } \right) =4.5\Rightarrow A\left( \overset { \triangle }{ ACD } \right) =7.5\\ $$ it means
$$A\left( \overset { \triangle }{ ACD } \right) =A\left( \overset { \triangle }{ ABC } \right) =12\Rightarrow A\left( ABEF \right) =5.5\\ $$
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Obviously,$\triangle EFC$ and $\triangle AFD$ similar triangles so $$\frac { A\left( \overset { \triangle }{ EFC } \right) }{ A\left( \overset { \triangle }{ AFD } \right) } =\frac { { \left( 2m \right) }^{ 2 } }{ { \left( 3m \right) }^{ 2 } } =\frac { 4 }{ 9 } $$ anf we get that $$A\left( \overset { \triangle }{ AFD } \right) =4.5\Rightarrow A\left( \overset { \triangle }{ ACD } \right) =7.5\\ $$ it means
$$A\left( \overset { \triangle }{ ACD } \right) =A\left( \overset { \triangle }{ ABC } \right) =12\Rightarrow A\left( ABEF \right) =5.5\\ $$