How to derive the dynamics of $S_t$ in the Vasicek model?

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I’m a grad quant student and I’m struggling with this model

$$dX_t = k(\mu-Χ_t)dt+\sigma dW_t$$

I’m given this Vasicek model And after applying Itô's lemma with $$S_t = e^X$$

$$\frac{dS_t}{S_t}=[k(\mu-\ln(S_t))+\frac{1}{2}\sigma^2]d_t+\sigma dW_t $$

They get to this equation

$$ S_t = e^{\ln(S)e^{-k(t-s)}+ \mu \left(1-e^{-k(t-s)}\right)+\sigma\int_{s}^{t}e^{-k(t-u)}\,dW_u}$$

And I’ve got no clue how to derive this last equation after Itô's lemma, could anyone enlighten me? No intermediate steps are shown in my professor's slides.

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As suggested in the comments, let $g(x,t) = e^{kt}x$. The relevant derivatives are: $$\begin{align*} g_t(x,t) &= ke^{kt}x \\ g_x(x,t) &= e^{kt} \\ g_{xx}(x,t) &= 0 \end{align*}$$ Applying Itô's lemma to $S_t = g(X_t, t)$, we get: $$\begin{align*} dS_t &= ke^{kt}X_t dt + e^{kt} dX_t \\ &= ke^{kt} X_t dt + e^{kt}[k (\mu - X_t)dt + \sigma dW_t] \\ &= k\mu e^{kt}dt + \sigma e^{kt} dW_t \end{align*}$$ Thus, $$S_t -S_0 = e^{kt} X_t - X_0 = \mu e^{kt} + \sigma \int_0^t e^{ks}dW_s$$ So that $$X_t = X_0 e^{-kt} + \mu + \sigma e^{-kt} \int_0^t e^{ks}dW_s$$