Given: $X_1$ and $X_2$ are the roots of the equation $ax^2+bx+c = 0$ $a\neq 0$
expand $X_1^3 + X_2^3$ using the parameters a,b and c
Here's what I tried to do:
$X_1^3 + X_2^3 = $ $(X_1\cdot X_2)\cdot(X_1^2-X_1\cdot X_2+X_2^2)$ From Viet's formulas: $(X_1\cdot X_2)(X_1^2-X_1\cdot X_2+X_2^2)$ = $\frac{-b}{a}\cdot(X_1^2+X_2^2- \frac{c}{a})=$ $\frac{c\cdot b}{a^2}\cdot(X_1^2+X_2^2)$
And this i all I can do the answer in my textbook is $\frac{3abc-b^3}{a^3}$
HINT:
Use
$$p^3+q^3=(p+q)^3-3pq(p+q)$$
Alternatively,
$x^3=y$ and cubing $$(ax^2+bx)^3=(-c)^3$$
$$-c^3=a^3(x^3)^2+b^3(x^3)+3ab(x^3)(ax^2+bx)=a^3y^2+y(b^3-3abc)$$
$$a^3y^2+y(b^3-3abc)+c^3=0$$ whose roots are $x_1^3,x_2^3$