$$y(t) + t \int_0^t y(v)dv = 1 + \int_0^t vy(v)dv$$
I found the answer to be $y(t) = \cos{t}$. I have no idea how they go this answer. I would appreciate any suggestions how to solve this.
$$y(t) + t \int_0^t y(v)dv = 1 + \int_0^t vy(v)dv$$
I found the answer to be $y(t) = \cos{t}$. I have no idea how they go this answer. I would appreciate any suggestions how to solve this.
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Differentiate (left side) - (right side) twice and you'll get $$ y'' + y = 0$$ so $y(t) = a \cos(t) + b \sin(t) $. Plug that in to your integral equation and you'll find that you need $a=1$, $b=0$.