How to find the fundamental matrix for this differential equation?

Question

I have the following differential equation: $$t^2x''(t)-4tx'(t)+6x(t)=0$$ and two linearly independent solutions, $x_1(t)=t^2$ and $x_2(t)=t^3$ in the interval $(0, \infty )$. I'm then asked to find the fundamental matrix for $$A(t)=\left( \begin{array}{ccc} 0 & 1 \\ -6t^{-1} & 4t^{-1} \\ \end{array} \right)$$ I know how to find the fundamental matrix when an equation is in the form $y'(t)=A(t)y(t)$ but can't see how to put this into that form. Can anyone offer any advice?