How to find the invariant factors of a matrix given its Jordan canonical form?

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Suppose we have a matrix $A \in M_{12}(\mathbb{C})$ whose Jordan canonical form is

$$J_1(0) \oplus J_1(0) \oplus J_2(0) \oplus J_2(0) \oplus J_1(\sqrt{2}) \oplus J_1(\sqrt{2}) \oplus J_1(-\sqrt{2}) J_1(-\sqrt{2}) \oplus J_1(i\sqrt{2}) \oplus J_1(-i\sqrt{2})$$

Then how would we go about finding the invariant factors given this? And how do we tell how many invariant factors there are going to be?

I know that the first is going to the minimal polynomial which must be

$$m_A(t) = t^2(t^2-2)(t^2+2)$$

and they have to product together to give the characteristic polynomial, which is

$$p_A(t)= t^6(t^2-2)^2(t^2+2)$$

Thanks in advance!