I was wondering how I would find the inverse of the following function, since the e has a co-efficient:
$\frac{e^x}{1+2e^x}=y$
I got as far as $\ln y+\ln(2e^x) = \ln e^x$, which would be changed into:
$\ln y + \ln(2e^x) = x\ln e$ (or just $x$)
But where do I go from here?
$\frac{e^x}{1+2e^x}=\frac1{e^{-x}+2}$, so $e^{-x}=\frac1y-2$.