
The diagram above ^^^
I am stumped as how to find the shaded area as I can only infer one angle and one side from the diagram.
Help would be much appreciated

The diagram above ^^^
I am stumped as how to find the shaded area as I can only infer one angle and one side from the diagram.
Help would be much appreciated
Because $OB=BC$ the triangle OBC is isosceles.
If you draw a perpendicular from $B$ to $OC$ you know (due to isosceles) that the intersection point $M$ is in the middle of $OC$
In the new triangle $OBM$ you know a length $OM=9/2=4.5cm$ and two angles: $OBM=80/2=40$ and $BMO=90$. Then you can find $OB$ and angle $BOC$.
The rest is easy. If you want the area of shaded then find the area of a circular sector and substract the area of the triangle. For the perimeter, now you have $BOC$ and distance $BC=OB$.