Can I ask (I guess the simplest question) how to find $x$ in the following
\begin{equation} \Big(\frac{n}{n-1}\Big)^{x-1} = 0 \end{equation}
If I take $\log$ both sides, I get $-\infty$ on the the R.H.S.
If I inverse the equations, I get $\infty$ on R.H.S.
Well if we just look at the equation in a general context, we get $B^x=0$, in which case, there's no solution. You can never raise anything to any power and get 0. Exponential functions have an asymptote on the x-axis.