For matrix equation Ax = b (A is a $3×4$ matrix, x is $4×1$ vector , b is $3×1$ vector).
now, we have matrix A , vector b and already know that the third value of x is zero. How can we get the vector x by using the generalized inverse matrix of A .
For matrix equation Ax = b (A is a $3×4$ matrix, x is $4×1$ vector , b is $3×1$ vector).
now, we have matrix A , vector b and already know that the third value of x is zero. How can we get the vector x by using the generalized inverse matrix of A .
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Let us assume that $G_{4\times 3}$ is a generalized inverse of $A$.
than we know that, $$AGA=A$$ which means that for any $x$ $$AGAx=Ax$$ $$\implies AGb=b\quad(\because Ax=b)$$
which shows that $Gb=x$.
so, once you the generalized inverse of $A$ then $Gb$ will be the solution.
That $x=Gb$ is always a solution.
If you want a unique generalized inverse, Moore-Penrose inverse instead of generalized inverse will do the necessary.