How to give a sketch of this new set?

Question

Now I need to give the sketch of this set: $B = \{(x,y) \in \Bbb{R}^2: x^2+y^2\le 4\}$ intersect with $\{(x,y) \in \Bbb{R}^2: x^2+y^2\le 4y\}$. I guess that the first set is the interior of the circle of center $(0,0)$ and radius $2$ included its borders, isn't it? But the second set is not clear as well. may you help me please?

Answer 1

the second set is also a circle just compare it with $x^2+y^2 +2gx+2fy+c=0$ where $g=0,f=-2 $ radius=$\sqrt{(g^2+f^2-c)}$ center=$(-g,-f)$ i.e.