Let $R$ be the region in the first quadrant bounded by the graph of $y=2\sqrt{x}$, the horizontal line $y = 6$, and the $y$-axis. Region $R$ is the base of a solid. For each $y$, where $0 \le y \leq 6$, the cross section of the soild taken perpendicular to the $y$-axis is a rectangle whose height is 3 times the lenght of its base in region $R$. This is from 2010 AP Calculus BC free-response question 4. I solved this problem correctly, but I don't know how to graph it. Could you help explain how?
2026-05-06 02:17:32.1778033852
How to graph this problem?
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@Andre did the answer completely so I did just the picture of your solid: