You can parametrise: get the equation in terms of $t$. Or you could convert to polar coordinates: use the form $r$ as a function of $\theta$.
However, in general, this can be complicated. Instead you need to solve for $Y$ and graph all solutions simultaneously, remembering that you can only graph $Y$ as a function of $X$.
You can parametrise: get the equation in terms of $t$. Or you could convert to polar coordinates: use the form $r$ as a function of $\theta$.
However, in general, this can be complicated. Instead you need to solve for $Y$ and graph all solutions simultaneously, remembering that you can only graph $Y$ as a function of $X$.
$$\begin{align} X^2 + Y^2 &= 4 \\ Y^2 &= 4 - X^2 \\ Y &= \pm \sqrt{4-X^2} \end{align}$$
Hence graph $$Y_1 =+\sqrt{4-X^2} \\ Y_2 = -\sqrt{4-X^2}$$
(Obviously omit the $+$ on the calculator.)
This method is not always possible. I recommend using Desmos.com—go check it out. Here’s how simple it is!