How to model function with unknown exponents?

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I know the Cobb-Douglass function which describes the production quantity:

$$Q(K, L) = A \cdot K^\alpha \cdot L^\beta$$

Also I do know multiple assignments of K (Capital) and L (Labour) to Q (Quantity):

Q | 10 | 30 | 60 | 80 | 95 | 108
K | 10 | 10 | 10 | 10 | 10 |  10
L |  1 |  2 |  3 |  4 |  5 |   6

Because we have three unknown variables and we have jumps in Q I decided to choose three different assignments:

$$Q(10, 1) = 10$$ $$Q(10, 3) = 60$$ $$Q(10, 5) = 95$$

Now when I insert the first assignment I can get the value of A:

$$\implies 10 = A \cdot 10^\alpha \cdot 1^\beta \iff A = \frac{10}{10^\alpha \cdot 1^\beta}$$

However when I now use the second assignment to get or β I make some mistake:

$$ \implies 30 = \frac{10 \cdot 2^\alpha 10^\beta}{1^\alpha 10^\beta} \iff 3 = \frac{2^\alpha 10^\beta}{1^\alpha 10^\beta} \iff 3 = \frac{2^\alpha}{1^\alpha} \iff 3 = \frac{1^\alpha \cdot 1^\alpha}{1^\alpha} \iff 3 = 1^\alpha \iff \alpha = \frac{log(3)}{log(1)}$$

Which does not seem correct to me.

Where did the mistake(s) occur?

Bodo

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There are several mistakes. First, $A=\frac{10}{10^\alpha1^\beta}=10^{1-\alpha}$ (this was correct!). But now, you use this for the second assignment, and I think you mixed up $\alpha$ and $\beta$. You should have had $Q(10,2)=30$ $\Leftrightarrow$ $10^{1-\alpha}\cdot10^\alpha\cdot2^\beta=30$ $\Leftrightarrow$ $10\cdot 2^\beta=30$ $\Leftrightarrow$ $2^\beta=3$ $\Leftrightarrow$ $\beta=\frac{\log3}{\log2}$. There was a further mistake in your calculation: $2^\alpha\neq1^\alpha\cdot1^\alpha$!