Let $\gamma=\sup\{\xi_n\}=\{\xi_n<\omega_1: n\in \omega\}$. How to prove $\gamma < \omega_1$?
Thanks for your help.
Since $\gamma=\bigcup_{n\in\omega}\xi_n$, it’s the union of countably many countable sets and is therefore countable; thus, it must be less than $\omega_1$.
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Since $\gamma=\bigcup_{n\in\omega}\xi_n$, it’s the union of countably many countable sets and is therefore countable; thus, it must be less than $\omega_1$.