How to Prove these Product to Sum Trig Identities

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$$ \sin(a)\cos(b) = \frac{1}{2}(\sin(a-b) + \sin(a+b)) $$

$$ \sin(a)\sin(b) = \frac{1}{2}(\cos(a-b) - \cos(a+b)) $$

$$ \cos(a)\cos(b) = \frac{1}{2}(\cos(a-b) + \cos(a+b)) $$

How do you derive these formulas from other Trig Identities such as any of:

  • Angle Addition Identities
  • Pythagorean Trig Identity
  • Half Angle Identities
  • Double Angle Identities

Or, if it can't be proven from other identities, what's the simplest way to prove them? Would prefer not to have a geometric proof from scratch for these, and be able to remember them by just remembering other more basic ones.

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Thanks to commenters for explaining this:

$$\begin{align} \sin(a-b)&=\sin(a)\cos(b)−\sin(b)\cos(a) \\ \\ \sin(a+b)&=\sin(a)\cos(b)+\sin(b)\cos(a) \\ \\ \sin(a-b) + \sin(a+b) &= 2\sin(a)\cos(b) \\ \\ \sin(a)\cos(b) &= \frac{\sin(a-b) + \sin(a+b)}{2} \end{align}$$