Theorem:
The negative of any even integer is even.
proof:
Suppose $n$ is an even integer. By definition of even, $n$ is even $\iff \exists k \in\mathbb{Z}$ such that $n = 2k$. We must show that the negative of $n$ is even. Then $n = 2k$ $= -(n) = -(2k)$ $= -n = -2k$ $= -n = 2(-k)$. Let $-k = r$, notice that $r$ is an integer because it's the product of integers $-1$ and $k$. Since $-n = 2r$ follows the definition of even, the negative of n is even.
How can we abbreviate this to take less space? When quoting definitions, I have a tendency to quote its entirety.
Correctly applying a definition does not necessarily involve quoting the thing. For example, here's a sample proof:
Let $n$ be an arbitrary even integer. Then for some integer $k,$ we have $n=2k.$
Let $m$ denote $-k.$ So, $m$ is an integer and $-n=-2k=2m;$ that is, $-n$ is even.
Hence, every even integer's negation is even.
(For example, given the even integer
-24, its negation24is also even.)By the way, the given theorem is not well-worded: does "the negative of the even integer $-6$ (i.e., minus six)" equal $6$ (but this is not negative) or $-6$ (but this is not the negation of $-6$)?
Addendum corresponding to the OP's edit
This is a nicely-written proof, except that $$n = 2k = -(n) = -(2k) = -n = -2k = -n = 2(-k)$$ is incoherent. Try to write the string of equalities such that they read more linearly.