The spiral curve that needs to be rotated. The curve has an initial radius of 0.2 and a final radius of 1.0. It rotates for 2 revolutions and has to start at the positive y-axis and end at the positive y-axis too. My current equations are: $$ \begin{cases} x&=-(0.8u+0.2) \cos(4\pi ~ u) \\ y&=~(0.8u+0.2) \sin(4\pi ~ u) \end{cases} \qquad u \in [0,1] $$
2026-04-07 00:02:09.1775520129
How to rotate spiral curve by 90 degrees such that the curve starts on the positive Y-axis?
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