How to set equations containing factorials?

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I recently encountered a problem involving the construction of equations involving factorials or combinatorial numbers. I recall reading somewhere (although I cannot recall the reference) that this can be a tricky subject.

In a particular scenario, the author of the problem suggested that the solution would be $x=1$. To construct the simplest equation possible with this solution, the author proposed using $x-1=0$. Subsequently, the author manipulated this equation to obtain:

\begin{align} (x-1)^2 &= 0 \\ x^2 - 2x + 1 &= 0 \\ x(x-2) + 1 &= 0 \\ x(x-2) &= -1 \\ \frac{x!}{(x-1)!}\frac{(x-2)!}{(x-3)!} &= -1 \\ x!(x-2)! &= -(x-1)!(x-3)! \end{align}

However, upon substituting $x=1$ into the equations, we encounter expressions such as $(-1)!$ and $(-2)!$, which do not make sense in this context.

My question is: Am I missing something, or is the author's approach incorrect? Any insights or explanations would be greatly appreciated. Thank you very much.

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The factorial can be generalized to complex arguments using the gamma function: $n!=\Gamma(n+1)$. This function has poles at all non-positive integers, so the factorial of a negative integer diverges. Thus you’re right to think that this attempt at constructing an equation with solution $x=1$ is misguided, since substituting $x=1$ leads to expressions that are divergent even when appropriately generalized.