I was wondering if someone could possibly help me figure out how to show $e^{2 \pi i \theta}$ is not algebraic when $\theta$ is irrational.
Thanks!
I was wondering if someone could possibly help me figure out how to show $e^{2 \pi i \theta}$ is not algebraic when $\theta$ is irrational.
Thanks!
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Use Lindemann–Weierstrass theorem
http://en.wikipedia.org/wiki/Lindemann%E2%80%93Weierstrass_theorem
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Note that as stated the result is not correct. For example, there is a real number $t$ such that $\cos(2\pi t)$ is equal to $\dfrac{3}{5}$, and it can be shown that $t$ is not rational. But if $\theta$ is an irrational algebraic number, then indeed $e^{2\pi i\theta}$ is transcendental.