How to simplify $3^{(2\log_335)}$

Question

$3^{2\log_35}$

How do I simplify this? This is what I have done so far:

$2\log_35=\log_35^2=\log_3(25)$

$3^{\log_3(25)}$

What do I do from here? And the answer is one of these mixed solutions:

$0$

$-2$

$-\frac\pi4$

$\frac1{x+2}$

$\pm \frac4 {25}$

$25$

$30°$

$2$

$3$

$5$

$\pi$

$\frac\pi3$

$(-\infty, 2)$

$4(x+1)^2+3$

$-\frac{\sqrt2}2$

$-\frac{\sqrt3}2$

$\frac{\sqrt2}2$

Answer 1

$\displaystyle m\log a=\log a^m$ when both the logarithms remain defined

$$\displaystyle\implies3^{(2\log_35)}=3^{\log_3(5^2)}$$

Now $\displaystyle a^{\log_ab}=b$ when the logarithm remains defined