Solve this equation for $x$:
$$\left|x \sqrt{1-x^2} +x \right| = \sqrt{1+x^2}$$
I'm having a problem getting rid of the square root!
Solve this equation for $x$:
$$\left|x \sqrt{1-x^2} +x \right| = \sqrt{1+x^2}$$
I'm having a problem getting rid of the square root!
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Provided $-1\le x\le 1$, you get:
\begin{align} \left|x \sqrt{1-x^2} +x \right| = \sqrt{1+x^2}\\ \left|x \left(\sqrt{1-x^2} +1\right) \right| = \sqrt{1+x^2}\\ |x|\left(\sqrt{1-x^2} +1\right) = \sqrt{1+x^2}\\ x^2\left(\sqrt{1-x^2} +1\right)^2 = 1+x^2\\ x^2\left(1-x^2+2\sqrt{1-x^2}+1\right) = 1+x^2\\ 2x^2\sqrt{1-x^2}=x^4-x^2+1\\ 4x^4\left(1-x^2\right)=\left(x^4-x^2+1\right)^2 \end{align}