I have tried the following:
$s = \ln{\left(x + \ln{\left(x + \ln{\left(x + ...\right)}\right)}\right)}$
$s = \ln{\left(s + x\right)}$
$e^{s} = s + x$
However, I am unsure as to how to proceed.
Thank you.
I have tried the following:
$s = \ln{\left(x + \ln{\left(x + \ln{\left(x + ...\right)}\right)}\right)}$
$s = \ln{\left(s + x\right)}$
$e^{s} = s + x$
However, I am unsure as to how to proceed.
Thank you.
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A solution of $e^s = x+s$ is given by $$ s=-x-W(-e^{-x})\qquad (x\geq 1)$$ where $W$ is the Lambert W-function.