How to sketch $(x^2-2)^2 + (y^2-2)^2=2$

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$$\left(x^{2}-2\right)^{2}+\left(y^{2}-2\right)^{2}=2$$

Pretty much as per the title. Was set as a graph sketching exercise. Can see that it will have symmetry around all 4 axes but unclear as to how I would go about sketching this. I guess I could look at key points e.g. $(1,1), (\sqrt{3},1)$ but not sure it's a great method. Any help appreciated

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First, graph $\left(x-2\right)^{2}+\left(y-2\right)^{2}=2$.

Then graph $\left(x-2\right)^{2}+\left(y^{2}-2\right)^{2}=2$.

Then graph $\left(x^{2}-2\right)^{2}+\left(y^{2}-2\right)^{2}=2$.

(At each step explain how the graph is transformed.)