I am trying to solve this question but not able to figure out how to approach it.
$100^{63} \mod\ {63}$
Please help.
I am trying to solve this question but not able to figure out how to approach it.
$100^{63} \mod\ {63}$
Please help.
On
As $\displaystyle63=9\cdot7$ and $(7,9)=1$
$\displaystyle100\equiv1\pmod9$
$\displaystyle100\equiv2\pmod7,\implies100^3\equiv2^3\equiv1$
$\displaystyle\implies100^{\text{lcm}(1,3)}\equiv1\pmod{7\cdot9}$
Alternatively, using Carmichael function, $\displaystyle\lambda(63)=6\implies10^6\equiv1\pmod{63}$ as $(10,63)=1$
$\displaystyle\implies100^3=(10^2)^3=10^6\equiv1\pmod{63}$
In either case, $\displaystyle100^{3r}\equiv1\pmod{63}$ for any integer $r\ge0$
Hint: $$100\equiv37 \mod 63$$ $$100^2\equiv46 \mod 63$$ $$100^3\equiv1 \mod 63$$ $$100^4\equiv37 \mod 63$$
Note: I don't know much about Modular arithmetic but I consulted Wolfram Alpha, and found this