I am given the following equation to solve
$$32^x - 8 = 2 \cdot 4^x$$
which one can simplyfy to $$2^{5x}-2^3 = 2^{2x+1}$$
where do we go from here? If we had something like $$2^{2x} - 5 \cdot 2^x + 6 = 0$$
we could convert it to a quadratic, but not in this case.
Any help is highly appreciated.
You can still convert it into a polynomial, since
$$2^{5x} - 8 = 2\cdot 2^{2x}$$
converts to
$$y^5-8=2y^2$$
if you introduce $y=2^x$.