I have done this. is this correct? If wrong, what is needed to be changed?
$(a+bc)(d'+dc)(a'+d')$
$ = ad'a' + abcd' + bcd'a' + bcbcd'$
$ = d' + abcd' + bcd'a' + bcbcd'$
$ = d' + bcd' (a + a' + bc)$
$ = d' + bcd' \cdot (1)$
$ = d'(1+bc)$
$ = d'$
2026-03-25 09:47:09.1774432029
How to solve $(a+bc)(d'+bc)(a'+d')$ using Boolean algebra
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