Suppose I have an equation which looks like:
$$|x-2| + |2x+1| = 3$$
or,
$$|x-1| + |x-3| - |5x-1| = 2$$
How should I solve such problems?
What i do is generally a kind of "hit-and-trial" method but is there an even better method to do so?
Thanks!
Suppose I have an equation which looks like:
$$|x-2| + |2x+1| = 3$$
or,
$$|x-1| + |x-3| - |5x-1| = 2$$
How should I solve such problems?
What i do is generally a kind of "hit-and-trial" method but is there an even better method to do so?
Thanks!
The way that always works (especially for inequalities of the same type, and also for nonlinear stuff in the $| \cdot |$ and for multiple variables) is doing case analysis, such that for each $| \cdot |$ you have 2 cases to look at.
In your first example that would be:
Case 1: $x-2>0$ and $2x+1>0$
Case 2: $x-2>0$ and $2x+1<0$
Case 3: $x-2<0$ and $2x+1>0$
Case 4: $x-2<0$ and $2x+1<0$
it is some work, but often a lot of cases are not important, because they are impossible, such as Case 2 here.