Suppose Boyet, a basketball player, has an 85% chance of making free throw. Over the whole game, he attempts 5 free throws. What is the probability that he will miss at least one of them?
So I'm literally having a hard time understanding what how to get the independent probability on this problem. How would I know what's the two events that intersected in this situation? How can I use the independent formula in this one?
Total probability is equal to the chance the desired situation happens plus the chance that it does not happen.
P(missing no shots) + P(missing 1 or more shots) = 1P(missing 1 or more shots) = 1 - P(missing no shots)Each free throw is independent of each other with the same probability
P(missing no shots) = P(making one shot)^(attempted shots)As the probability of making one shot is given as 85% and the number of attempted shots is given as 5, we can evaluate the this equation.
P(missing no shots) = (0.85)^5P(missing 1 or more shots) = 1-0.4437053125P(missing 1 or more shots) = 0.5562946875 = 55.62946875%