How to solve for these 2 functions?

Question

Given $f(x) = \sqrt {x^3 - 4}$, solve for $g(x)$ and $h(x)$ where $f(x) = (g \circ h)(x)$

Answer 1

$h(x)=x^3-4$ and $g(x)=\sqrt{x}.$

Answer 2

$h(x)=x$ and $g(x)=f(x)$ or vice-versa

I'll do you one better:

$f(x)=(g\circ h \circ i)(x)$: $g(x) = \sqrt{x}$;$h(x) = x-4$;$i(x)=x^3$

Don't forget:

$h(x)=x+\texttt{(Meaningless Constant)}$ and $g(x)=f(x)-\texttt{(Meaningless Constant)}$