Can anyone walk me through how to find the parametric curve for
x=3*sin(2t), y = 1.5*cos(t)?
If the parametric equations were x = 3*sin(t), y = 1.5*cos(t) I know I would solve it the following way:
x/3 = sin(t), y/1.5 = cos(t) --> (x/3)^2 + (y/1.5)^2 = 1
What's really confusing me is the 2 that is being multiplied to t.
Thanks in advance
$$\dfrac xy=4\sin t$$
So, $$(x/4y)^2+(2y/3)^2=1$$