how to solve the following: $x^{(\frac{1}{4}+\log_{6}{1})}=\sqrt6$

Question

how to solve the following: $x^{(\frac{1}{4}+\log_{6}{1})}=\sqrt6$

I know that the answer is $36$ as I plug it into the equation it turns out to be true.

But what I do not understand is the process in which I obtain the answer $36$ and would like some assistance in figuring out what process I should take in order to obtain the answer

Answer 1

HINT:

Taking logarithm wrt base $2,$

$$\log_2(x^2)=2+\log_25=\cdots+\log_2(2^2\cdot5)$$