By using the Newton Method and use the function $y=x\log x-\frac{1}{4}$
$$x_{n+1}=x_n-\frac{y_n}{y'_n}$$
then
$$x_{n+1}=\frac{x_n+1/4}{1+\log x_n}$$
at $x_0=1$ to get
$$x1=1.25$$
$$x_2=1.226348288$$
$$x_3=1.226161263$$
$$x_4=1.226161251$$
$$x_5=1.226161251$$
7
Bumbble Comm
On
The right answer was given above. We can also write $$x = \frac{1/4}{W(1/4)},$$
where $W$ denotes the Lambert W function defined as an inverse of $f(z) = z \exp z$, e.g. $$z = W (z\exp z) \iff f(z) = z \exp z.$$
By using the Newton Method and use the function $y=x\log x-\frac{1}{4}$ $$x_{n+1}=x_n-\frac{y_n}{y'_n}$$
then $$x_{n+1}=\frac{x_n+1/4}{1+\log x_n}$$ at $x_0=1$ to get $$x1=1.25$$ $$x_2=1.226348288$$ $$x_3=1.226161263$$ $$x_4=1.226161251$$ $$x_5=1.226161251$$