I have no idea of how to solve $x^x=2$, and more generally, $x^x=n$, $n\in\mathbb{C}$.
I have tried many things, like taking log, exponentiating, etc. But none of these works. Any help would be appreciated :)
2026-04-05 06:21:00.1775370060
How to solve $x^x=2$
42 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in LOGARITHMS
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