Nice to meet you, this is my first question in this site.
I now can draw $A\to B\to C$ but stuck at $A\to B\to C\to D$. Let me show you my graph: $A\to B\to C$.
It's easy to see that $A$, $B$ and $C$ are not independent to each other, but conditional on $B$, then $A$ and $C$ would be independent, which can deduce the Markov property: $P(C|B,A)=P(C|B)$.
So, how to draw $A\to B\to C\to D$ in a similar way, or more generally, draw $X_1\to X_2\to \dots\to X_n$? Or is it possible?
Just found the answer by myself:
And here is $X_1\to X_2\to\dots\to X_{10}$: