How can I write $210\in\mathbb Z[\sqrt{-1}]$ as a product of prime elements?
Progress
I factored $2\in\mathbb Z[i]=(1-i)(1+i)$ and $5\in\mathbb Z[i]=(2-i)(2+i)$. I cannot do it for $3$ and $7$ though.
How can I write $210\in\mathbb Z[\sqrt{-1}]$ as a product of prime elements?
I factored $2\in\mathbb Z[i]=(1-i)(1+i)$ and $5\in\mathbb Z[i]=(2-i)(2+i)$. I cannot do it for $3$ and $7$ though.
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If $p$ is a prime with $p \equiv 3 \bmod 4$, then $p$ is a prime element in $\mathbb{Z}[i]$. This is because $x^2+1$ is irreducible mod $p$.