How would you solve these logarithmic problems

Question

Problem 1

Problem 2:

IF 5^X = 15 then what would be 5^2x-1

Answer 1

Problem 2:

$5^{2x-1} = \frac{(5^x)^2}{5}$

So if you know $5^x$, you can get the rest.

Problem 1:

$\log(1) = 0 $ So any real solutions come from $x^2+4x-60 = 0$ or $x^2 -5x +5 = 1$