Hyperbolic cylinder

83 Views Asked by At

I'm reading the first chapter of the book "Geometry and spectra of compact Riemann surfaces" by P. Buser. On page 9, he wrote

Parametrize $\gamma$ and $\gamma^\prime$ with unit speed and opposite boundary orientation such that $\gamma(0) = a$ and $\gamma^\prime(0) = b$.

Why is "opposite boundary orientation"? I though that it should be the same orientation according to the picture he gave. Did I misunderstand something here? enter image description here

Thank you!

1

There are 1 best solutions below

0
On BEST ANSWER

it is the opposite orientation as part of the boundary. A consistent orientation would be, say, the path through $a,$ then a line segment, then the path through $b$ backwards of the drawn arrow, then another line segment. Riemann surfaces are orientable, the interior of the bounded region should be thought of as having a little arrow indicating a direction of rotation.