I am working with exponential equations and models.

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The original problem What I have tried From the information given in the problem we have the points $(5,360)$ and $(20,1000)$

I found a solution online that used the solution to find k shown on the right of the whiteboard. I know that this is the correct answer because that is the answer in the book and I worked it out another way and got the same answer.

$\frac{360}{1000}=\frac{A_0e^{k5}}{A_0e^{k20}}$
$\frac{9}{25}=e^{-15k}$

$\ln\left(\frac{9}{25}\right)=-15k$

$k=\frac{\ln\left(\frac{9}{25}\right)}{-15}$

I would just like to understand why we are allowed to do that.

While trying to understand I tried what is written on the right in red, but that is not the solution that I got on the right. Can someone please help me understand why that isn't correct

$360=A_0e^{5k}$

$0=A_0e^{5k}-360$

$1000=A_0e^{20k}$

$0=A_0e^{20k}-1000$

$A_0e^{5k}-360=A_0e^{20k}-1000$

$e^{15k}=640$

$\ln(640)=15k$

$k=\frac{\ln(640)}{15}$

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You are making fundamental mistakes.

Firstly, you have treated $A_0$ as if it is $1$

If you proceeded to first find $k$, you would get $k= 0.068110$,
and to find $A_0$, you'd solve$A_0*e^{(5*0.068110)}=360 \Longrightarrow A_0 =256$

and you'd find that $A_0e^{5k} = 360, A_0e^{20k} = 1000$

secondly, you can't subtract as $e^{15k} = 1000-360$,
you should revise the laws of exponents